Integrand size = 17, antiderivative size = 209 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=a^4 d^3 x+\frac {1}{3} a^3 d \left (4 c d^2+3 a e^2\right ) x^3+\frac {1}{4} a^4 e^3 x^4+\frac {6}{5} a^2 c d \left (c d^2+2 a e^2\right ) x^5+\frac {2}{3} a^3 c e^3 x^6+\frac {2}{7} a c^2 d \left (2 c d^2+9 a e^2\right ) x^7+\frac {3}{4} a^2 c^2 e^3 x^8+\frac {1}{9} c^3 d \left (c d^2+12 a e^2\right ) x^9+\frac {2}{5} a c^3 e^3 x^{10}+\frac {3}{11} c^4 d e^2 x^{11}+\frac {1}{12} c^4 e^3 x^{12}+\frac {3 d^2 e \left (a+c x^2\right )^5}{10 c} \]
a^4*d^3*x+1/3*a^3*d*(3*a*e^2+4*c*d^2)*x^3+1/4*a^4*e^3*x^4+6/5*a^2*c*d*(2*a *e^2+c*d^2)*x^5+2/3*a^3*c*e^3*x^6+2/7*a*c^2*d*(9*a*e^2+2*c*d^2)*x^7+3/4*a^ 2*c^2*e^3*x^8+1/9*c^3*d*(12*a*e^2+c*d^2)*x^9+2/5*a*c^3*e^3*x^10+3/11*c^4*d *e^2*x^11+1/12*c^4*e^3*x^12+3/10*d^2*e*(c*x^2+a)^5/c
Time = 0.07 (sec) , antiderivative size = 197, normalized size of antiderivative = 0.94 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=\frac {x \left (3465 a^4 \left (4 d^3+6 d^2 e x+4 d e^2 x^2+e^3 x^3\right )+924 a^3 c x^2 \left (20 d^3+45 d^2 e x+36 d e^2 x^2+10 e^3 x^3\right )+297 a^2 c^2 x^4 \left (56 d^3+140 d^2 e x+120 d e^2 x^2+35 e^3 x^3\right )+66 a c^3 x^6 \left (120 d^3+315 d^2 e x+280 d e^2 x^2+84 e^3 x^3\right )+7 c^4 x^8 \left (220 d^3+594 d^2 e x+540 d e^2 x^2+165 e^3 x^3\right )\right )}{13860} \]
(x*(3465*a^4*(4*d^3 + 6*d^2*e*x + 4*d*e^2*x^2 + e^3*x^3) + 924*a^3*c*x^2*( 20*d^3 + 45*d^2*e*x + 36*d*e^2*x^2 + 10*e^3*x^3) + 297*a^2*c^2*x^4*(56*d^3 + 140*d^2*e*x + 120*d*e^2*x^2 + 35*e^3*x^3) + 66*a*c^3*x^6*(120*d^3 + 315 *d^2*e*x + 280*d*e^2*x^2 + 84*e^3*x^3) + 7*c^4*x^8*(220*d^3 + 594*d^2*e*x + 540*d*e^2*x^2 + 165*e^3*x^3)))/13860
Time = 0.41 (sec) , antiderivative size = 209, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {475, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \left (a+c x^2\right )^4 (d+e x)^3 \, dx\) |
| \(\Big \downarrow \) 475 |
| \(\displaystyle \int \left (c^4 e^3 x^{11}+3 c^4 d e^2 x^{10}+4 a c^3 e^3 x^9+c^3 d \left (c d^2+12 a e^2\right ) x^8+6 a^2 c^2 e^3 x^7+2 a c^2 d \left (2 c d^2+9 a e^2\right ) x^6+4 a^3 c e^3 x^5+6 a^2 c d \left (c d^2+2 a e^2\right ) x^4+a^4 e^3 x^3+a^3 d \left (4 c d^2+3 a e^2\right ) x^2+a^4 d^3\right )dx+\frac {3 d^2 e \left (a+c x^2\right )^5}{10 c}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle a^4 d^3 x+\frac {1}{4} a^4 e^3 x^4+\frac {1}{3} a^3 d x^3 \left (3 a e^2+4 c d^2\right )+\frac {2}{3} a^3 c e^3 x^6+\frac {3}{4} a^2 c^2 e^3 x^8+\frac {6}{5} a^2 c d x^5 \left (2 a e^2+c d^2\right )+\frac {1}{9} c^3 d x^9 \left (12 a e^2+c d^2\right )+\frac {2}{5} a c^3 e^3 x^{10}+\frac {2}{7} a c^2 d x^7 \left (9 a e^2+2 c d^2\right )+\frac {3 d^2 e \left (a+c x^2\right )^5}{10 c}+\frac {3}{11} c^4 d e^2 x^{11}+\frac {1}{12} c^4 e^3 x^{12}\) |
a^4*d^3*x + (a^3*d*(4*c*d^2 + 3*a*e^2)*x^3)/3 + (a^4*e^3*x^4)/4 + (6*a^2*c *d*(c*d^2 + 2*a*e^2)*x^5)/5 + (2*a^3*c*e^3*x^6)/3 + (2*a*c^2*d*(2*c*d^2 + 9*a*e^2)*x^7)/7 + (3*a^2*c^2*e^3*x^8)/4 + (c^3*d*(c*d^2 + 12*a*e^2)*x^9)/9 + (2*a*c^3*e^3*x^10)/5 + (3*c^4*d*e^2*x^11)/11 + (c^4*e^3*x^12)/12 + (3*d ^2*e*(a + c*x^2)^5)/(10*c)
3.5.92.3.1 Defintions of rubi rules used
Int[((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp [d*n*c^(n - 1)*((a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Int[ExpandIntegran d[((c + d*x)^n - d*n*c^(n - 1)*x)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d}, x] && IGtQ[p, 0] && IGtQ[n, 0] && LeQ[n, p]
Time = 2.18 (sec) , antiderivative size = 240, normalized size of antiderivative = 1.15
| method | result | size |
| norman | \(\frac {c^{4} e^{3} x^{12}}{12}+\frac {3 c^{4} d \,e^{2} x^{11}}{11}+\left (\frac {2}{5} e^{3} c^{3} a +\frac {3}{10} d^{2} e \,c^{4}\right ) x^{10}+\left (\frac {4}{3} d \,e^{2} c^{3} a +\frac {1}{9} d^{3} c^{4}\right ) x^{9}+\left (\frac {3}{4} a^{2} c^{2} e^{3}+\frac {3}{2} d^{2} e \,c^{3} a \right ) x^{8}+\left (\frac {18}{7} a^{2} c^{2} d \,e^{2}+\frac {4}{7} d^{3} c^{3} a \right ) x^{7}+\left (\frac {2}{3} e^{3} c \,a^{3}+3 d^{2} e \,a^{2} c^{2}\right ) x^{6}+\left (\frac {12}{5} d \,e^{2} c \,a^{3}+\frac {6}{5} d^{3} a^{2} c^{2}\right ) x^{5}+\left (\frac {1}{4} e^{3} a^{4}+3 d^{2} e c \,a^{3}\right ) x^{4}+\left (d \,e^{2} a^{4}+\frac {4}{3} a^{3} c \,d^{3}\right ) x^{3}+\frac {3 d^{2} e \,a^{4} x^{2}}{2}+a^{4} d^{3} x\) | \(240\) |
| default | \(\frac {c^{4} e^{3} x^{12}}{12}+\frac {3 c^{4} d \,e^{2} x^{11}}{11}+\frac {\left (4 e^{3} c^{3} a +3 d^{2} e \,c^{4}\right ) x^{10}}{10}+\frac {\left (12 d \,e^{2} c^{3} a +d^{3} c^{4}\right ) x^{9}}{9}+\frac {\left (6 a^{2} c^{2} e^{3}+12 d^{2} e \,c^{3} a \right ) x^{8}}{8}+\frac {\left (18 a^{2} c^{2} d \,e^{2}+4 d^{3} c^{3} a \right ) x^{7}}{7}+\frac {\left (4 e^{3} c \,a^{3}+18 d^{2} e \,a^{2} c^{2}\right ) x^{6}}{6}+\frac {\left (12 d \,e^{2} c \,a^{3}+6 d^{3} a^{2} c^{2}\right ) x^{5}}{5}+\frac {\left (e^{3} a^{4}+12 d^{2} e c \,a^{3}\right ) x^{4}}{4}+\frac {\left (3 d \,e^{2} a^{4}+4 a^{3} c \,d^{3}\right ) x^{3}}{3}+\frac {3 d^{2} e \,a^{4} x^{2}}{2}+a^{4} d^{3} x\) | \(247\) |
| gosper | \(\frac {1}{12} c^{4} e^{3} x^{12}+\frac {3}{11} c^{4} d \,e^{2} x^{11}+\frac {2}{5} a \,c^{3} e^{3} x^{10}+\frac {3}{10} x^{10} d^{2} e \,c^{4}+\frac {4}{3} x^{9} d \,e^{2} c^{3} a +\frac {1}{9} x^{9} d^{3} c^{4}+\frac {3}{4} a^{2} c^{2} e^{3} x^{8}+\frac {3}{2} x^{8} d^{2} e \,c^{3} a +\frac {18}{7} x^{7} a^{2} c^{2} d \,e^{2}+\frac {4}{7} x^{7} d^{3} c^{3} a +\frac {2}{3} a^{3} c \,e^{3} x^{6}+3 x^{6} d^{2} e \,a^{2} c^{2}+\frac {12}{5} x^{5} d \,e^{2} c \,a^{3}+\frac {6}{5} x^{5} d^{3} a^{2} c^{2}+\frac {1}{4} a^{4} e^{3} x^{4}+3 x^{4} d^{2} e c \,a^{3}+x^{3} d \,e^{2} a^{4}+\frac {4}{3} a^{3} c \,d^{3} x^{3}+\frac {3}{2} d^{2} e \,a^{4} x^{2}+a^{4} d^{3} x\) | \(248\) |
| risch | \(\frac {1}{12} c^{4} e^{3} x^{12}+\frac {3}{11} c^{4} d \,e^{2} x^{11}+\frac {2}{5} a \,c^{3} e^{3} x^{10}+\frac {3}{10} x^{10} d^{2} e \,c^{4}+\frac {4}{3} x^{9} d \,e^{2} c^{3} a +\frac {1}{9} x^{9} d^{3} c^{4}+\frac {3}{4} a^{2} c^{2} e^{3} x^{8}+\frac {3}{2} x^{8} d^{2} e \,c^{3} a +\frac {18}{7} x^{7} a^{2} c^{2} d \,e^{2}+\frac {4}{7} x^{7} d^{3} c^{3} a +\frac {2}{3} a^{3} c \,e^{3} x^{6}+3 x^{6} d^{2} e \,a^{2} c^{2}+\frac {12}{5} x^{5} d \,e^{2} c \,a^{3}+\frac {6}{5} x^{5} d^{3} a^{2} c^{2}+\frac {1}{4} a^{4} e^{3} x^{4}+3 x^{4} d^{2} e c \,a^{3}+x^{3} d \,e^{2} a^{4}+\frac {4}{3} a^{3} c \,d^{3} x^{3}+\frac {3}{2} d^{2} e \,a^{4} x^{2}+a^{4} d^{3} x\) | \(248\) |
| parallelrisch | \(\frac {1}{12} c^{4} e^{3} x^{12}+\frac {3}{11} c^{4} d \,e^{2} x^{11}+\frac {2}{5} a \,c^{3} e^{3} x^{10}+\frac {3}{10} x^{10} d^{2} e \,c^{4}+\frac {4}{3} x^{9} d \,e^{2} c^{3} a +\frac {1}{9} x^{9} d^{3} c^{4}+\frac {3}{4} a^{2} c^{2} e^{3} x^{8}+\frac {3}{2} x^{8} d^{2} e \,c^{3} a +\frac {18}{7} x^{7} a^{2} c^{2} d \,e^{2}+\frac {4}{7} x^{7} d^{3} c^{3} a +\frac {2}{3} a^{3} c \,e^{3} x^{6}+3 x^{6} d^{2} e \,a^{2} c^{2}+\frac {12}{5} x^{5} d \,e^{2} c \,a^{3}+\frac {6}{5} x^{5} d^{3} a^{2} c^{2}+\frac {1}{4} a^{4} e^{3} x^{4}+3 x^{4} d^{2} e c \,a^{3}+x^{3} d \,e^{2} a^{4}+\frac {4}{3} a^{3} c \,d^{3} x^{3}+\frac {3}{2} d^{2} e \,a^{4} x^{2}+a^{4} d^{3} x\) | \(248\) |
1/12*c^4*e^3*x^12+3/11*c^4*d*e^2*x^11+(2/5*e^3*c^3*a+3/10*d^2*e*c^4)*x^10+ (4/3*d*e^2*c^3*a+1/9*d^3*c^4)*x^9+(3/4*a^2*c^2*e^3+3/2*d^2*e*c^3*a)*x^8+(1 8/7*a^2*c^2*d*e^2+4/7*d^3*c^3*a)*x^7+(2/3*e^3*c*a^3+3*d^2*e*a^2*c^2)*x^6+( 12/5*d*e^2*c*a^3+6/5*d^3*a^2*c^2)*x^5+(1/4*e^3*a^4+3*d^2*e*c*a^3)*x^4+(d*e ^2*a^4+4/3*a^3*c*d^3)*x^3+3/2*d^2*e*a^4*x^2+a^4*d^3*x
Time = 0.27 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.17 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=\frac {1}{12} \, c^{4} e^{3} x^{12} + \frac {3}{11} \, c^{4} d e^{2} x^{11} + \frac {1}{10} \, {\left (3 \, c^{4} d^{2} e + 4 \, a c^{3} e^{3}\right )} x^{10} + \frac {1}{9} \, {\left (c^{4} d^{3} + 12 \, a c^{3} d e^{2}\right )} x^{9} + \frac {3}{2} \, a^{4} d^{2} e x^{2} + \frac {3}{4} \, {\left (2 \, a c^{3} d^{2} e + a^{2} c^{2} e^{3}\right )} x^{8} + a^{4} d^{3} x + \frac {2}{7} \, {\left (2 \, a c^{3} d^{3} + 9 \, a^{2} c^{2} d e^{2}\right )} x^{7} + \frac {1}{3} \, {\left (9 \, a^{2} c^{2} d^{2} e + 2 \, a^{3} c e^{3}\right )} x^{6} + \frac {6}{5} \, {\left (a^{2} c^{2} d^{3} + 2 \, a^{3} c d e^{2}\right )} x^{5} + \frac {1}{4} \, {\left (12 \, a^{3} c d^{2} e + a^{4} e^{3}\right )} x^{4} + \frac {1}{3} \, {\left (4 \, a^{3} c d^{3} + 3 \, a^{4} d e^{2}\right )} x^{3} \]
1/12*c^4*e^3*x^12 + 3/11*c^4*d*e^2*x^11 + 1/10*(3*c^4*d^2*e + 4*a*c^3*e^3) *x^10 + 1/9*(c^4*d^3 + 12*a*c^3*d*e^2)*x^9 + 3/2*a^4*d^2*e*x^2 + 3/4*(2*a* c^3*d^2*e + a^2*c^2*e^3)*x^8 + a^4*d^3*x + 2/7*(2*a*c^3*d^3 + 9*a^2*c^2*d* e^2)*x^7 + 1/3*(9*a^2*c^2*d^2*e + 2*a^3*c*e^3)*x^6 + 6/5*(a^2*c^2*d^3 + 2* a^3*c*d*e^2)*x^5 + 1/4*(12*a^3*c*d^2*e + a^4*e^3)*x^4 + 1/3*(4*a^3*c*d^3 + 3*a^4*d*e^2)*x^3
Time = 0.04 (sec) , antiderivative size = 270, normalized size of antiderivative = 1.29 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=a^{4} d^{3} x + \frac {3 a^{4} d^{2} e x^{2}}{2} + \frac {3 c^{4} d e^{2} x^{11}}{11} + \frac {c^{4} e^{3} x^{12}}{12} + x^{10} \cdot \left (\frac {2 a c^{3} e^{3}}{5} + \frac {3 c^{4} d^{2} e}{10}\right ) + x^{9} \cdot \left (\frac {4 a c^{3} d e^{2}}{3} + \frac {c^{4} d^{3}}{9}\right ) + x^{8} \cdot \left (\frac {3 a^{2} c^{2} e^{3}}{4} + \frac {3 a c^{3} d^{2} e}{2}\right ) + x^{7} \cdot \left (\frac {18 a^{2} c^{2} d e^{2}}{7} + \frac {4 a c^{3} d^{3}}{7}\right ) + x^{6} \cdot \left (\frac {2 a^{3} c e^{3}}{3} + 3 a^{2} c^{2} d^{2} e\right ) + x^{5} \cdot \left (\frac {12 a^{3} c d e^{2}}{5} + \frac {6 a^{2} c^{2} d^{3}}{5}\right ) + x^{4} \left (\frac {a^{4} e^{3}}{4} + 3 a^{3} c d^{2} e\right ) + x^{3} \left (a^{4} d e^{2} + \frac {4 a^{3} c d^{3}}{3}\right ) \]
a**4*d**3*x + 3*a**4*d**2*e*x**2/2 + 3*c**4*d*e**2*x**11/11 + c**4*e**3*x* *12/12 + x**10*(2*a*c**3*e**3/5 + 3*c**4*d**2*e/10) + x**9*(4*a*c**3*d*e** 2/3 + c**4*d**3/9) + x**8*(3*a**2*c**2*e**3/4 + 3*a*c**3*d**2*e/2) + x**7* (18*a**2*c**2*d*e**2/7 + 4*a*c**3*d**3/7) + x**6*(2*a**3*c*e**3/3 + 3*a**2 *c**2*d**2*e) + x**5*(12*a**3*c*d*e**2/5 + 6*a**2*c**2*d**3/5) + x**4*(a** 4*e**3/4 + 3*a**3*c*d**2*e) + x**3*(a**4*d*e**2 + 4*a**3*c*d**3/3)
Time = 0.20 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.17 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=\frac {1}{12} \, c^{4} e^{3} x^{12} + \frac {3}{11} \, c^{4} d e^{2} x^{11} + \frac {1}{10} \, {\left (3 \, c^{4} d^{2} e + 4 \, a c^{3} e^{3}\right )} x^{10} + \frac {1}{9} \, {\left (c^{4} d^{3} + 12 \, a c^{3} d e^{2}\right )} x^{9} + \frac {3}{2} \, a^{4} d^{2} e x^{2} + \frac {3}{4} \, {\left (2 \, a c^{3} d^{2} e + a^{2} c^{2} e^{3}\right )} x^{8} + a^{4} d^{3} x + \frac {2}{7} \, {\left (2 \, a c^{3} d^{3} + 9 \, a^{2} c^{2} d e^{2}\right )} x^{7} + \frac {1}{3} \, {\left (9 \, a^{2} c^{2} d^{2} e + 2 \, a^{3} c e^{3}\right )} x^{6} + \frac {6}{5} \, {\left (a^{2} c^{2} d^{3} + 2 \, a^{3} c d e^{2}\right )} x^{5} + \frac {1}{4} \, {\left (12 \, a^{3} c d^{2} e + a^{4} e^{3}\right )} x^{4} + \frac {1}{3} \, {\left (4 \, a^{3} c d^{3} + 3 \, a^{4} d e^{2}\right )} x^{3} \]
1/12*c^4*e^3*x^12 + 3/11*c^4*d*e^2*x^11 + 1/10*(3*c^4*d^2*e + 4*a*c^3*e^3) *x^10 + 1/9*(c^4*d^3 + 12*a*c^3*d*e^2)*x^9 + 3/2*a^4*d^2*e*x^2 + 3/4*(2*a* c^3*d^2*e + a^2*c^2*e^3)*x^8 + a^4*d^3*x + 2/7*(2*a*c^3*d^3 + 9*a^2*c^2*d* e^2)*x^7 + 1/3*(9*a^2*c^2*d^2*e + 2*a^3*c*e^3)*x^6 + 6/5*(a^2*c^2*d^3 + 2* a^3*c*d*e^2)*x^5 + 1/4*(12*a^3*c*d^2*e + a^4*e^3)*x^4 + 1/3*(4*a^3*c*d^3 + 3*a^4*d*e^2)*x^3
Time = 0.28 (sec) , antiderivative size = 247, normalized size of antiderivative = 1.18 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=\frac {1}{12} \, c^{4} e^{3} x^{12} + \frac {3}{11} \, c^{4} d e^{2} x^{11} + \frac {3}{10} \, c^{4} d^{2} e x^{10} + \frac {2}{5} \, a c^{3} e^{3} x^{10} + \frac {1}{9} \, c^{4} d^{3} x^{9} + \frac {4}{3} \, a c^{3} d e^{2} x^{9} + \frac {3}{2} \, a c^{3} d^{2} e x^{8} + \frac {3}{4} \, a^{2} c^{2} e^{3} x^{8} + \frac {4}{7} \, a c^{3} d^{3} x^{7} + \frac {18}{7} \, a^{2} c^{2} d e^{2} x^{7} + 3 \, a^{2} c^{2} d^{2} e x^{6} + \frac {2}{3} \, a^{3} c e^{3} x^{6} + \frac {6}{5} \, a^{2} c^{2} d^{3} x^{5} + \frac {12}{5} \, a^{3} c d e^{2} x^{5} + 3 \, a^{3} c d^{2} e x^{4} + \frac {1}{4} \, a^{4} e^{3} x^{4} + \frac {4}{3} \, a^{3} c d^{3} x^{3} + a^{4} d e^{2} x^{3} + \frac {3}{2} \, a^{4} d^{2} e x^{2} + a^{4} d^{3} x \]
1/12*c^4*e^3*x^12 + 3/11*c^4*d*e^2*x^11 + 3/10*c^4*d^2*e*x^10 + 2/5*a*c^3* e^3*x^10 + 1/9*c^4*d^3*x^9 + 4/3*a*c^3*d*e^2*x^9 + 3/2*a*c^3*d^2*e*x^8 + 3 /4*a^2*c^2*e^3*x^8 + 4/7*a*c^3*d^3*x^7 + 18/7*a^2*c^2*d*e^2*x^7 + 3*a^2*c^ 2*d^2*e*x^6 + 2/3*a^3*c*e^3*x^6 + 6/5*a^2*c^2*d^3*x^5 + 12/5*a^3*c*d*e^2*x ^5 + 3*a^3*c*d^2*e*x^4 + 1/4*a^4*e^3*x^4 + 4/3*a^3*c*d^3*x^3 + a^4*d*e^2*x ^3 + 3/2*a^4*d^2*e*x^2 + a^4*d^3*x
Time = 9.49 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.08 \[ \int (d+e x)^3 \left (a+c x^2\right )^4 \, dx=x^3\,\left (a^4\,d\,e^2+\frac {4\,c\,a^3\,d^3}{3}\right )+x^4\,\left (\frac {a^4\,e^3}{4}+3\,c\,a^3\,d^2\,e\right )+x^9\,\left (\frac {c^4\,d^3}{9}+\frac {4\,a\,c^3\,d\,e^2}{3}\right )+x^{10}\,\left (\frac {3\,c^4\,d^2\,e}{10}+\frac {2\,a\,c^3\,e^3}{5}\right )+a^4\,d^3\,x+\frac {c^4\,e^3\,x^{12}}{12}+\frac {3\,a^4\,d^2\,e\,x^2}{2}+\frac {3\,c^4\,d\,e^2\,x^{11}}{11}+\frac {6\,a^2\,c\,d\,x^5\,\left (c\,d^2+2\,a\,e^2\right )}{5}+\frac {2\,a\,c^2\,d\,x^7\,\left (2\,c\,d^2+9\,a\,e^2\right )}{7}+\frac {3\,a\,c^2\,e\,x^8\,\left (2\,c\,d^2+a\,e^2\right )}{4}+\frac {a^2\,c\,e\,x^6\,\left (9\,c\,d^2+2\,a\,e^2\right )}{3} \]
x^3*((4*a^3*c*d^3)/3 + a^4*d*e^2) + x^4*((a^4*e^3)/4 + 3*a^3*c*d^2*e) + x^ 9*((c^4*d^3)/9 + (4*a*c^3*d*e^2)/3) + x^10*((2*a*c^3*e^3)/5 + (3*c^4*d^2*e )/10) + a^4*d^3*x + (c^4*e^3*x^12)/12 + (3*a^4*d^2*e*x^2)/2 + (3*c^4*d*e^2 *x^11)/11 + (6*a^2*c*d*x^5*(2*a*e^2 + c*d^2))/5 + (2*a*c^2*d*x^7*(9*a*e^2 + 2*c*d^2))/7 + (3*a*c^2*e*x^8*(a*e^2 + 2*c*d^2))/4 + (a^2*c*e*x^6*(2*a*e^ 2 + 9*c*d^2))/3